determine the mass in grams of colbate III nitrate, Co(No3) 3 (M co(no3)3 = 244.96) that contains the same nummber of moles of oxygen, O2, as 13.52 grams of potassium sulfate, K2So4 if Mk2so4= 174.259

Answer 1

Cobalt(III) nitrate = Co(NO₃)₃

Potassium sulfate = K₂SO₄

First, we'll find the moles of oxygen (O, no O2) contained in 13.52 g of K2SO4

13.52 g K₂SO₄ x 1 mol K₂SO₄ / 174.259 g x 4 mol O / mol K₂SO₄ = 0.3103 mols O

Next, we find how many grams of Co(NO₃)₃ contains 0.3103 mols of O

0.3103 mol O x 1 mol Co(NO₃)₃ / 9 mol O x 244.96 g Co(NO₃)₃ / mol = 8.446 g Co(NO₃)₃