please do this problem

Question

Determine whether the results appear to have statistical​ significance, and also determine whether the results appear to have practical significance.One of a​ botanist's hybridization experiments with peas yielded 736 offspring with 192 of those peas​ (or 26​%) having yellow pods. According to genetic​ theory, 25% of the offspring peas should have yellow pods.

Answer 1

Practical Significance: We expect 25% of 736 (184) to be yellow. We observe that 192 are. Practically speaking, this is not a significant difference.

Statistical Significance:

Let the null hypothesis Ho be the following: p = 0.25 (proportion of yellow peas is 25%).

And the alternate hypothesis Ha: p=/= 0.25 (proportion is not 25%)

Note that this is a two tailed test because we are testing if it is not equal to something, a one-tailed test is for greater than or less than.

Recall the formula for a Z-Score: z = (po - p)/√(p*(1-p))/n) = (0.26-0.25)/√((0.25*0.75)/736) = .01/0.01596 = 0.627

Using a Z-Score table or a calculator in Excel, we see p = 0.53 so this is not statistically significant. For it to be significant at the 0.05 level (95% confidence), we would need a p-value less than 0.05.