AMANI J.
asked 06/12/22Electrochemistry
Given Cu2+/Cu=0.34V and Cu2+/Cu+=0.153V, calculate the equilibrium constant for the reaction Cu + Cu2+<->2Cu2+
1 Expert Answer
J.R. S. answered 06/12/22
Ph.D. University Professor with 10+ years Tutoring Experience
Cu2+ + 2e- ==> Cu Eº = 0.34 V (cathode)
Cu2+ + e- ==> Cu+ Eº = 0.15 V (anode)
Overall:
Cu2+ + 2Cu+ ==> Cu + 2Cu2+
Eº = cathode - anode = 0.34 - 0.15
E = 0.19 V
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J.R. S.
06/12/22