Need help now pls

Question

Point U is on line segment \overline{TV}TV. Given TU=4,TU=4, UV=5x,UV=5x, and TV=3x+6,TV=3x+6, determine the numerical length of \overline{TV}.TV

Answer 1

Answer 2

First, note that:

TV = TU + UV, so:

3x + 6 = 4 + 5x

-3x - 4 = -4 - 3x

0 + 2 = 0 + 2x

2 = 2x

1 = x

So, TV = 3x + 6 = 3*1 + 6 = 3 + 6 = 9.