J.R. S. answered 06/06/22
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = ?
m = mass = 1990 g
C = specific heat of water = 4.184 J/gº (joules / gram / degree)
∆T = change in temperature
Solving for q, we have ...
q = (1990 g)(4.184 J/gº)(8.9º)
q = 74103 J (joules)