Raymond B. answered 06/04/22
Tutor
5
(2)
Math, microeconomics or criminal justice
cscAsecA/2 = (1/sinA)(1/cosA)/2
= 1/2sinAcosA
= 1/sin2A
= csc2A
0000 A.
asked 06/04/22Raymond B. answered 06/04/22
Math, microeconomics or criminal justice
cscAsecA/2 = (1/sinA)(1/cosA)/2
= 1/2sinAcosA
= 1/sin2A
= csc2A
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