Please someone answer this question

Question

If I contain 1.37 moles of gas in a container with a volume of 52.9 liters and at a temperature of 393.K, what is the pressure inside the container in atm?

Answer 1

Ideal gas law: PV = nRT

P = pressure in atm = ?

V = volume in L = 52.9 L

n = mols = 1.37 mols

R = gas constant = 0.0821 Latm/Kmol

T = temp in Kelvin = 393K

Solving for P, we have...

P = nRT / V = (1.37)(0.0821)(393) / 52.9

P = 0.835 atm (3 sig. figs.)