What are the larger of the triangle’s acute angles

Question

In a right triangle, sin (2x + 1)° = cos (x - 10)°. Find the larger of the triangle's two acute angles.

Answer 1

Answer 2

sin(2x+1) = cos(x-10)

2x+1 + x-10 = 90

3x =90-1+10 = 99

x = 99/3 = 33

2x+1 = 67 degrees

x-10 = 23 degrees

sin67 = 0.9205

cos23 = 0.9205

the two acute angles are 23 and 67 degrees

the larger angle is 2x+1 = 2(33)+1 = 67 degrees