Limiting Reagent

Question

If 7.45 g of N2 and 4.20 g of O2 react according to:

2N₂ + O₂ ⮕ 2N₂O

a)     Which reactant is in excess?

b)     Calculate the mass of product formed.

Answer 1

More of the same. Learn to do these yourself.

2N2 + O2 ==> 2N2O

(a) Find limiting reactant

Find mols N2 present and divide that by 2

Find mols O2 present and divide that by 1

Whichever is less is the limiting reactant and thus, the other is in excess

(b) Use the mols of the limiting reactant and the stoichiometry (mol ratios) of the balanced equation to find mols of N2O formed. Multiply mols N2O by the molar mass of N2O to find grams N2O.