Percentage Yield

Question

When 9 g of hydrogen reacts with oxygen, 73 g of water is produced.



1. What is the theoretical yield of water?
2. What is the actual yield?
3. What is the percentage yield?

Answer 1

You can't calculate part (b), the actual yield. That is something that is experimentally determined, or the value must be provided to you in the question.

2H₂ + O₂ ==> 2H₂O ... balanced equation

a). 9 g H2 x 1 mol H2 / 2 g x 2 mol H2O / 2 mol H2 x 18 g H2O / mol = 81 g H2O produced (theoretical yld)

b). actual yield = 73 g (given in the question)

c). % yield = actual / theoretical (x100%) = 73 g / 81 g (x100%) = 90% yield