consecutive odd integers

Question

Find four consecutive odd integers such that the sum of the second and third is 19 greater than the fourth. What is the first number?

Answer 1

The difference between every odd number is 2. Let the first four consecutive numbers be n, n+2, n+4, n+6

Since the sum of the second and third number is 19 greater than the fourth number, we can form the equation as

n+2 + n+4 = n+6 + 19

n = 19

Hence, the first odd number is 19.