Find the equation of a circle with a center of (2,-3) and passes through the point (3,0)

Answer 1

(x-2)^2 + (y+3)^2 = r^2

fo sovlve for r^2 plug in the point (3,0)

1 + 9 = r^2 = 10

the circle's equation is

(x-2)^2 + (y+3)^2 = 10

Answer 2

The radius of the circle is sqrt[(3-2)²+3²]=R

The equation of the circle then is (x-2)² + (y+3)² = R²