Two ships sleep a poor at the same time the first ship sales on a bearing of 58° at 16 kn and the second on a bearing of 148° at 24 kn how far apart are they after 1.5 hours

Question

Neglect the curvature of the earth. Round to the nearest nautical mile as needed

Answer 1

The difficulty here is that the problem is giving us kilonewtons, which is a measure of force. What is needed is velocity.

Answer 2

First ship travels 16*1.5 miles. This will be the first leg of a triangle.

The secong ship travels 24*1.5 miles. This will be the second leg in a triangle.

The angle between these 2 legs is 148-58 = 90

So, in this particular case it is a right triangle.

The distance between the ships is a hypotenuse of this triangle.

So d = sqrt( (16*1.5)^2 + (24*1.5)^2 ) = 43 miles