J.R. S. answered 05/12/22
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C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)
molar mass ethanol = 46.1 g / mol
15.0 g C2H5OH x 1 mol / 46.1 g x 3 mol H2O / 1 mol C2H5OH x 18 g H2O/mol = 17.6 g H2O