J.R. S. answered 05/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
V1M1 = V2M2 (be sure all units match)
(175 ml)(1.6 M) = (1000 ml)(x M)
x = 0.28 M
Konstantino P.
asked 05/10/22If you dilute 175 mL of a 1.6 M solution of LiCl(aq) to 1.0 L, determine the new concentration of the solution?
J.R. S. answered 05/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
V1M1 = V2M2 (be sure all units match)
(175 ml)(1.6 M) = (1000 ml)(x M)
x = 0.28 M
Paolo S. answered 05/11/22
PhD student with 5+ years of Tutoring and Teaching Chemistry Labs
You can easily reach out to [email protected] if you have any more questions.
Step 1. Rearrange M1V1 = M2V2
You are looking for the "new" concentration, which means M2.
Divide each side by V2 and get: M2= (M1V1)/V2
Step 2. Plug it in, be wary of the correct units
M2 = (0.175 L * 1.6 M)/ 1.0 L = 0.28 M
I prefer to keep it in L since we would divide by 1 L.
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