P(less than 4)=3/12 or 1/4. {1,2,3}
P(at least 4 or greater)=9/12 or 3/4. {4,5,6,7,8,9,10,11,12}
P(getting less than 4 on exactly 3 out of 6 tosses)=(1/4)^3 × (3/4)^3
Muriel S.
asked 05/10/22"Suppose that a die is made by marking the faces of a dodecahedron with the numbers 1-12. What is the probability that on exactly 3 out of 6 tosses a number less than 4 shows up?
P(less than 4)=3/12 or 1/4. {1,2,3}
P(at least 4 or greater)=9/12 or 3/4. {4,5,6,7,8,9,10,11,12}
P(getting less than 4 on exactly 3 out of 6 tosses)=(1/4)^3 × (3/4)^3
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