Margaret R. answered 05/09/22
Experienced Algebra, Statistics and Pre-Cal Tutor, HS and College
Margin of Error for proportions is calculated by:
Z * √((p-hat)(1-p-hat)/n)
Z is the z-value corresponding to the confidence level desired. In this case, there is not a specific confidence level mentioned, so this would assume the default CL of 95% for the middle 95% of values in a normal distribution, the z value is +/- 1,96, so use 1.96 to calculate ME.
p-hat is the sample proportion (in this case, .46)
n is the sample size (in this example, 733)
so set up the problem and compute: 1.96 (√((.46*.54)/733)