Round your final answer to one decimal place.

Question

Home Internet Access In a recent year, a study found that 77%

 of adults ages 18

–29

 had internet access at home. A researcher wanted to estimate the proportion of undergraduate college students (18

–29

 years) with access, so she randomly sampled 182

 undergraduates and found that 163

 had access. Estimate the true proportion with 90%

confidence. Round intermediate answers to five decimal places. Round your final answer to one decimal place.

Answer 1

n = 182 undergraduates

x = 163 selected

p = 163/182 = 0.89

z = 1.64 (This is from the z-table for critical values)

Use the one proportion confidence interval.

p ± z√p(1-p)/n = 0.89 ± 1.64√(0.89)(1-0.89)/182

= 0.89 ± 1.64√(0.89)(0.11)/182

= (0.887, 0.892)

We are 90% confident that the true proportion lies between 0.887 and 0.892.

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