Determine E° for a galvanic (voltaic) cell if ∆G° = -5.7 kJ/mol and n = 3. (F = 96,500 J/(V･mol))

Answer 1

∆Gº = - nFEº_cell

∆Gº = - 5.7 kJ/mol

n = 3

F = 96.500 J / Vmol x 1 kJ / 1000 J = 96.5 kJ / Vmol (keep units consistent with units of ∆Gº)

Solving for Eº, we have ...

Eº = ∆Gº / -nF

Eº = -5.7 kJ/mol / (-3)(96.5)

Eº = +0.02 V