J.R. S. answered 05/08/22
Ph.D. University Professor with 10+ years Tutoring Experience
We need more information to answer this question.
We need to know ...
freezing/melting point of octane
specific heats for the different phases of octane
∆Hfusion of octane
etc.
EIDT: THIS IS A TERRIBLE QUESTION IF NONE OF THE THERMOCHEMICAL DATA ARE PROVIDED
I was able to find the freezing point of octane to be -57ºC BUT unable to find the other information needed. Here is how to do the problem if YOU can find the missing data.
Assuming the solid octane is at -57ºC (and not lower than that, which isn't stated in the problem), you will have to find the ∆Hfusion for octane and use it in units of J/g or kJ/g.
q = ∆Hfusion x 79.2 g = heat needed to melt the solid octane (phase transition)
Then find the specific heat of liquid octane (C) and be sure it is in units of J/gº
q = (79.2 g)(specific heat in J/gº)(4.5º) = heat needed to get the liquid from -57º to -52.5º
Add the 2 results together to get your answer. It will be in units of Joules.
Zaiad W.
It does not give me any of that information. That is the exact question I am expected to answer.05/09/22