J.R. S. answered 05/07/22
Ph.D. University Professor with 10+ years Tutoring Experience
First, write the correctly balanced equation so that you can see the relationship of moles of H2 gas to moles of aluminum.
2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g) ... balanced equation (note: 2 mols Al => 3 mols H2 gas)
Next, use the 6 mols of Al provided, to find the moles of H2 gas that can be formed.
6 mols Al x 3 mols H2 / 2 mols Al = 9 moles of H2 gas is formed
Finally, convert the 9 moles of H2 gas into grams by using the molar mass of H2.
9 moles of H2 x 2 g H2 / mol H2 = 18 g H2 gas is formed