Michael C. answered 05/11/22
Professor, Statistics Using SPSS, and Research Methodology
98% CI for the mean = (96.470, 98.310)
Jay M.
asked 05/05/22question 10
The high temperatures (in degrees Fahrenheit) of a random sample of 10 small towns are:
| 96.3 |
| 96.4 |
| 99.5 |
| 98.7 |
| 97.5 |
| 97.6 |
| 97.2 |
| 96.8 |
| 96.5 |
| 97.4 |
Assume high temperatures are normally distributed. Based on this data, find the 98% confidence interval of the mean high temperature of towns. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).
98% C.I. =
Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Michael C. answered 05/11/22
Professor, Statistics Using SPSS, and Research Methodology
98% CI for the mean = (96.470, 98.310)
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