If AP = 3PB, then AP is 3/4 of the way from A(-6,-4) to B(0,8)
x coordinate of P is -6 + 3/4(0--6) = -6 + 3/4(6) = -6 + 9/2 = -1.5
y coordinate of P is -4 + 3/4(8--4) = -4 + 3/4 (12) = -4 + 9 = 5
P is (-1.5,5)
Jennifer O.
asked 05/05/22Given A(-6,-4) and B(0,8) on directed line segment AB, find point P on the segment such that AP = 3PB.
If AP = 3PB, then AP is 3/4 of the way from A(-6,-4) to B(0,8)
x coordinate of P is -6 + 3/4(0--6) = -6 + 3/4(6) = -6 + 9/2 = -1.5
y coordinate of P is -4 + 3/4(8--4) = -4 + 3/4 (12) = -4 + 9 = 5
P is (-1.5,5)
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