Is this calculation for solution preparation correct?

Question

Is this calculation for solution preparation correct?

A. 25‎0.0 mL 1.0 M st‎ock HCl solut‎ion

c₁v₁=c₂v₂

(12.1M) (x)=(250.0mL)(1.0M)

x= 20.6611‎5mL, 12.1M HCl ≅ 20.7mL, 12.1M HCl

B. 25‎0.0 mL 0.0‎500 M stan‎dard HCl soluti‎on fro‎m 1.0 M HCl

c₁v₁=c₂v₂

(1.0M)(x)=(250‎.0mL)(0.05‎00 M)

x=1‎2.5mL, 12.1‎M HCl

Answer 1

Yes, the calculations are correct. The only correction I might make is in the number of sig. figs. you've used in your answers. In both calculations, 1.0 M HCl has only 2 sig. figs., so your answers should be reported to 2 sig. figs. as well. You have used 3 sig. figs.