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Question

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH(aq)

 Calculate the amount of Ga(s)

 that can be deposited from a Ga(III)

 solution using a current of 0.260

 that flows for 40 min

mass: g

Answer 1

Ga³⁺ + 3e- ==> Ga(s)

Find the number of coulombs being applied:

2.60 A = 2.60 Coulombs / second = 2.60 C/s

40 min = 40 min x 60 sec/min = 2400 s

2400 s x 2.60 C/s = 6240 C

Convert this to moles of electrons:

6240 C x 1 mol e- / 96485 C = 0.0647 mols e-

Convert this to moles of Ga:

0.0647 mols e- x 1 mol Ga / 3 mols e- = 0.0216 mols Ga

Convert this to grams of Ga:

0.0216 mols Ga x 69.7 g Ga / mol = 1.50 g Ga