
Dayv O. answered 04/30/22
Caring Super Enthusiastic Knowledgeable Calculus Tutor
this one is not so hard
y'=1+(f'g-fg')/g2
more difficult was y=x2f(x)
it is not simply y'=2f(x)x2f(x)-1
taking integral (corrected) does not return function
y is variable x to a variable exponent 2f(x)
need to use properties of ln
lny=2f(x)lnx
y'/y=2f(x)/x+l2f'(x)lnx
y'=[x2f(x)](2f(x)/x+l2f'(x)lnx)