J.R. S. answered 04/30/22
Ph.D. University Professor with 10+ years Tutoring Experience
Ba(OH)2(s) <===> Ba2+(aq) + 2OH-(aq)
0................................0...................0..........I
.................................+x.................+2x.......C
..................................x..................2x.........E
Ksp = [Ba2+]{OH-]2
2.55x10-4 = (x)(2x)2 = 4x3
x3 = 6.375x10-5
x = 0.040
[OH-] = 0.080 M
[Ba2+] = 0.040 M