HELP WITH CHARLES LAW PLS

Question

A 5.86 L balloon at room temperature (20°C) is placed in a supercool freezer al 260 k.What is the balloon's new volume?

Answer 1

Charles law is essentially used when the pressure is held constant and can be written as ...

V1/T1 = V2/T2 (note: T must be in Kelvin)

V1 = 5.86 L

T1 = 20 + 273 = 293K

V2 = ?

T2 = 260K

5.86 L / 293K = V2 / 260K

V2 = 5.2 L