HELP IN CHEM AVOGADRO LAW!!!

Question

If 0.5 mol Argon gas occupies a volume of 8 L at STP what volume of gas would 30 grams of Argon gas have under the same conditions? (The molecular weight of Argon is 39.95 g/mol)

Answer 1

Avogadro's gas law basically says that the total number of atoms/molecules/moles of a gas is directly proportional to the volume when the temperature and pressure are constant.

We can write this as n1/V1 = n2/V2 where n1 and n2 are the initial and final moles, respectively and V1 and V2 are the initial and final volumes, respectively.

molar mass Ar = 39.95 g

30 g Ar x 1 mol / 39.95 g = 0.75 mols Ar

0.5 mol / 8 L = 0.75 mol / x L

x = 12 L