If 17.50 grams of a barium sulfate precipitate are produced, find the number of moles of Barium Nitrate that reacted.

Question

If 17.50 grams of a barium sulfate precipitate are produced, find the number of moles of Barium Nitrate that reacted.

Formula: CaSO4 (aq) + Ba(NO₃)₂ (aq) --> BaSO₄ (s) + Ca(NO₃)₂

Answer 1

CaSO₄(aq) + Ba(NO₃)₂(aq) ==> BaSO₄(s) + Ca(NO₃)₂ ... balanced equation

The mole ratio between BaSO₄ and Ba(NO₃)2 is 1:1, so for every mole of barium sulfate that precipitates, it will take 1 mole of barium nitrate

Moles BaSO₄ = 17.50 g BaSO₄ x 1 mol BaSO₄ / 233.4 g = 0.07498 moles BaSO₄

Moles Ba(NO₃)₂ that reacted = 0.07498 moles BaSO₄ x 1 mol Ba(NO₃)₂ / mole BaSO₄ = 0.07498 mols