
Yefim S. answered 04/28/22
Math Tutor with Experience
s = hcot45° - hcot67°; h = s/(1 - cot67°); h = 100/(1 - cot67°) = 174 feet
Ashtin W.
asked 04/28/22He then walks s = 100 feet further away and observes that the angle of elevation to the top of the antenna is B = 45° . Find the height of the antenna to the nearest foot. (Hint: Find x first.)
Yefim S. answered 04/28/22
Math Tutor with Experience
s = hcot45° - hcot67°; h = s/(1 - cot67°); h = 100/(1 - cot67°) = 174 feet
Mark M. answered 04/28/22
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram
h represents the height of the tower
d represents the distance from the tower to first observation point
h / d = tan 67°
h = d tan 67°
h / tan 67° = d (eq 1)
h / (d + 100) = tan 67°
h = (d + 100) tan 67°
h / tan 67° = d + 100
(h / tan 67°) - 100 = d (eq 2)
Set eq1 equal to eq 2 and solve for h.
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