Stoich question

Question

In a soda-acid fire extinguisher, concentrated sulfuric acid reacts with sodium hydrogen carbonate to produce carbon dioxide to produce carbon dioxide, sodium sulfate, and water._____H2SO4 + _____NaHCO3 --> _____ CO2 + _____ Na2SO4 + _____ H2OA.

How many moles of sodium hydrogen carbonate would be needed to react with 150.0 g of sulfuric acid? (Watch sfs)

How many moles of carbon dioxide would be needed to react with 150.0 g of sulfuric acid? (Watch sfs)

How many moles of sodium carbonate would be needed to react with 150.0 g of sulfuric acid? (Watch sfs)

How many moles of water (H2O) would be needed to react with 150.0 g of sulfuric acid? (Watch sfs)

Answer 1

H₂SO₄ + 2 NaHCO₃ ==> CO₂ + Na₂SO₄ + H₂O ... balanced equation

a) 150.0 g H₂SO₄ x 1 mol H₂SO₄ / 98.08 g x 2 mol NaHCO₃ / mol H₂SO₄ = 3.059 moles NaHCO₃ needed

b) carbon dioxide doesn't react with sulfuric acid. Maybe you meant how many moles of CO₂ are formed from 150.0 g of sulfuric acid.

150.0 g H₂SO₄ x 1 mol H₂SO₄ / 98.08 g x 1 mol CO₂ / mol H₂SO₄ = 1.529 moles CO₂ formed

c) sodium carbonate = Na₂CO₃ so the reaction would be Na₂CO₃ + H₂SO₄ ==> Na₂SO₄ + CO₂ + H₂O

150.0 g H₂SO₄ x 1 mol H₂SO₄ / 98.08 g x 1 mol Na₂CO₃/mol H₂SO₄ = 1.529 mols Na₂CO₃ needed

d) H₂O doesn't react with sulfuric acid. Maybe you meant how many moles of H₂O are formed from 150.0 g of sulfuric acid.

150.0 g H₂SO₄ x 1 mol H₂SO₄ / 98.08 g x 1 mol H₂O / mol H₂SO₄ = 1.529 mols H2O formed