J.R. S. answered 04/28/22
Ph.D. University Professor with 10+ years Tutoring Experience
MnO4- ==> MnO2 ... reduction half reaction
MnO4- + 4H2O ==> MnO2 + 2H2O + 4OH- ... balanced for Mn, O, and H in basic solution
MnO4- + 4H2O + 3e- ==> MnO2 + 2H2O + 4OH- ... balanced for Mn, O, and H and charge = balanced eq.
C2O42- ==> CO2 ... oxidation half reaction
C2O42- ==> 2CO2 + 2e- ... balanced for C, O and charge = balanced eq.
Multiply reduction by 2 and oxidation by 3 to equalize electrons, then add them together to get...
2MnO4- + 8H2O + 6e- + 3C2O42- ==> 2MnO2 + 4H2O + 8OH- + 6CO2 + 6e-
which simplifies to:
2MnO4- + 4H2O + 3C2O42- ==> 2MnO2 + 8OH- + 6CO2 ... BALANCED REDOX EQUATION