J.R. S. answered 04/28/22
Ph.D. University Professor with 10+ years Tutoring Experience
S2O32- ==> S4O62- ... oxidation half reaction
2S2O32- ==> S4O62- ... balanced for S and O
2S2O32- ==> S4O62- + 2e- ... balanced for mass and charge = fully balanced oxidation half reaction
(note: acid is not required for this half reaction. It would be required for the reduction half reaction of BiO3- =>Bi3+)