Complete and Balance the redox reaction in acidic soln.

Question

BiO3 ^- (aq)+S2O3 ^2- (aq)----->Bi^3+ (aq)+S4O6 ^2- (aq)

Answer 1

Wyzant won't allow a complete answer so here I provide the balanced equation for BiO₃^- => Bi³⁺ in acidic solution. I've provided the balanced equation for S2O32- => S4O62- in a separate question posted by you. Add them together to get the final balanced redox equation.

BiO₃^- ==> Bi³⁺... reduction half reaction (Bi goes from 5+ to 3+) already balanced for Bi

BiO₃^- ==> Bi³⁺ + 3H₂O ... balanced for Bi and O

BiO₃^- + 6H⁺ ==> Bi³⁺ + 3H₂O ... balanced for Bi, O and H

BiO₃^- + 6H⁺ +2e- ==> Bi³⁺ + 3H₂O ... balanced for mass and charge = fully balanced reduction half reaction

BiO₃^- + 6H⁺+ 2S₂O₃^2- ==> Bi³⁺ + 3H₂O + S₄O₆^2- ... BALANCED REDOX EQUATION