The Ksp for CdCO3 at a certain temperature is equal to 5.51x10^-12. What is the molar solubility of the compound at this temperature? (report answer to hundreths place in scientific notation)

Answer 1

CdCO₃(s) <==> Cd²⁺(aq) + CO₃^2-(aq)

Ksp = [Cd²⁺][CO₃^2-]

5.51x10^-12 = (x)(x) = x²

x = 2.35x10^-6 M = molar solubility of CdCO₃