In order to compute the Z score on these you want to use the equation
Z = (x – mean) / (standard deviation)
So for each of the test scores in this set of information that means taking
Z = (x – 72) / 6 in order to compute what the value would be.
So like for 57 for example, that calculation is
Z = (57 – 72) / 6 = -2.50
For the placement out of the 200 then you can convert the Z score into a p-value using either a normal distribution table or software like Excel, then multiply by 200.
So like for the example row of the score of 57, if you check on a Z table the p-value for the score of -2.5 is 0.0228. That means that 0.0228 * 200 = 5 students scored below that percentage.
And then 200 – 5 = 195 scored above.
You can apply that same logic to the remaining rows! :)