J.R. S. answered 04/21/22
Ph.D. University Professor with 10+ years Tutoring Experience
% composition is the % of each element present in the compound
For NaHCO3, from the periodic table, we have ...
Na = 23
H = 1
C = 12
O = 16 (x3) = 48
Total mass of 1 mole of NaHCO3 = 23 + 1 + 12 + 48 = 84 g/mole
% composition is as follows:
% Na = 23 / 84 (x100%) = 27%
% H = 1 / 84 (x100%) = 1%
% C = 12 / 84 (x100%) = 14%
% O = 48 / 84 (x100%) = 57%