J.R. S. answered • 04/21/22
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Iron(II) nitrate = Fe(NO3)2
Molar mass of iron(II) nitrate = 179.85 g / mole
Avogadro's number = 6.022x1023 molecules / mole
1). find the moles of iron(II) nitrate:
6.72x1027 molecules Fe(NO3)2 x 1 mole / 6.022x1023 molecules = 10412 moles (1.04x104 moles)
2). Convert 10412 moles Fe(NO3)2 to grams Fe(NO3)2:
1.04x104 mols Fe(NO3)2 x 179.85 g / mole = 2.00x106 g Fe(NO3)2
