PLEASE HELP WITH CHEMISTRY LIMITING REAGENTS PLS

Question

SiO2 (s) + 4 HF (g) -› SiF4(g) + 2 H2O (I)

(The Molar Mass of SiO2 is 60.09 grams/mol)

If we start with 6 moles of IF 'and 45 grams of SiO2 which is the limiting reagent?

Answer 1

One easy way to identify the limiting reagent is to divide the moles of each reactant by the corresponding coefficient in the balanced equation, and whichever value is less represents the limiting reagent.

SiO₂ (s) + 4 HF (g) -› SiF₄(g) + 2 H₂O (I) ... balanced equation

For SiO₂ we have: 45 g SiO₂ x 1 mol / 60.09 g = 0.749 moles (÷1->0.749)

For HF we have: 6 moles (÷4->1.5)

Since 0.749 is less than 1.5, SiO₂ is the limiting reagent.