HELP WITH HIGH SCHOOL STOICHEOMENTCRY PLEASE

Question

How many moles of Nitric Oxide are formed in the following reaction if you start with 42grams of Ammonia in a room filled with Oxygen Gas?

(the molar mass of Ammonia is 17.04 grams/mol)

2 NH₃ (g) + 3 O₂ (g)= 3 H₂0 (I) + N₂O₃ (g)

Answer 1

2 NH₃ (g) + 3 O₂ (g) == > 3 H₂0 (I) + N₂O₃ (g) ... balanced equation

molar mass NH3 = 17.04 g / mole

42 g NH₃ x 1 mole NH₃ / 17.04 g x 1 mol N₂O₃ / 2 mols NH₃ = 1.23 moles N₂O₃

Note: N₂O₃ is called dinitrogen trioxide, not nitric oxide. Nitric oxide is NO.

If you want the equation and solution for moles of NO, then it would be as follows:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ... balanced equation

42 g NH₃ x 1 mol NH₃ / 17.04 g x 4 mols NO / 4 mols NH₃ = 2.46 mols NO