Determine the equilibrium constant for a reaction at 200 K if ∆G° =20.1 kJ/mol. (R = 8.314 J/mol ･ K)

Answer 1

∆Gº = -RT ln K

∆Gº = 20.1 kJ/mol

R = 8.314 J/molK but we will convert to kJ/molK = 0.008314 kJ/molK

T = 200K

K = ?

20.1 kJ/mol = -(0.008314 kJ/molK)(200K) ln K

20.1 kJ/mol = -1.66 kJ/mol ln K

ln K = -12.1

K = 5.56x10^-6