
Lorellei S.
asked 04/19/22Kc Chem Questions
Which of the following is true ?
a. H2S04 is a strong acid because it has 2 hydrogens
b. Methyl amine (CH3NH2) is an example of an Arrhenius base.
c. Strong Bronsted- Lowry acids has negative pKa.
d. Weak bases are fully dissociated in water.
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Given 2 H2S(g) + CH4(g) -> 4 H2(g) + CS2(g) Kc = 5.27 * 10-8 at 973 K
What is Kc for formation of one mole of H2S(g) S at 973 K?
a. 4.36 X103
b. 9.49 x106
c. 2.3 x10-4
d. 1.15 x 10-4
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CuS will be soluble in acidic pH because
a. Cu+2 is a Lewis acid and S-2 is the counter-ion of strong acid , H2S.
b. S-2 is the conjugate base of a weak acid, H2S and Cu+2 is counter-ion of a strong base Cu(OH)2.
c. S-2 is the conjugate base of a weak acid HS- and Cu+2 is counter-ion of a strong base Cu(OH)2.
d. Cu+2 is a conjugate acid of a weak base Cu(OH)2 and S-2 is the counter-ion of strong acid, H2S.
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You need to use a salt that would have a neutral pH when dissolved in water . Which of the following will you choose ?
HF. pka = 3.18
Acetic Acid pka= 4.74
NH3. pkb = 4.74
CN- pkb = 4.79
a. sodium cyanide
b. ammonium fluoride
c. sodium fluoride
d. ammonium acetate
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Which statement below is true given below information?
CaCO3(s) -> CaO(s) + CO2(g) K= 1.9 X 10-23 at 298K
K =1 at 1200K
a. Changing pressure of the reaction vessel will not impact equilibria.
b. Reaction is an exothermic reaction.
c. Adding CaO(s) will favor the reverse reaction.
d. The reverse reaction is favored at 298 K.
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Which of the following is needed to form a coordination compound ?
a. complex ion
b. Arrhenius base
c. central metal ion
d. bidentate ligand
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Al(OH)3. is known to be amphoteric. What will be formed when it is reacted with aqueous NaOH ?
a. [Al(OH)4]+ soluble
b. soluble. Al+3 will be formed
c. no reaction. Al(OH)3 will only react with acid.
d. [Al(OH)4]+ insoluble
1 Expert Answer
J.R. S. answered 04/19/22
Ph.D. University Professor with 10+ years Tutoring Experience
Which of the following is true ?
b. Methyl amine (CH3NH2) is an example of an Arrhenius base. (it will produce OH- in solution)
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Given 2 H2S(g) + CH4(g) -> 4 H2(g) + CS2(g) Kc = 5.27 * 10-8 at 973 K
What is Kc for formation of one mole of H2S(g) S at 973 K?
c. 2.3 x10-4 (it will be the square root of the Kc)
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CuS will be soluble in acidic pH because
c. S-2 is the conjugate base of a weak acid HS- and Cu+2 is counter-ion of a strong base Cu(OH)2.
(the conjugate base of H2S is not S2-, but is HS-)
Too many others to answer at one sitting. Sorry.
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J.R. S.
04/19/22