Calculate each of the following quantities in 1.90 moles of H3PO4 .

Question

Moles of H=

Moles of O=

Atoms of P=

Atoms of O=

Answer 1

Hi Destiny,

We will find the moles of hydrogen, oxygen and phosphorus in the following way:

Multiply the moles of the substance by the number of molecules in the compound itself

Moles of H= 3 * 1.9 moles = 5.7 moles of H

Moles of O= 4 * 1.9 moles = 7.6 moles of O

Moles of P= 1 * 1.9 moles = 1.9 moles of P

To find the number of atoms of each molecule, we will multiply the moles by Avogadro's number, which tells us that 1 moles is equal to 6.022 × 10^(23) atoms.

Atoms of P = 1.9 moles of P * ( (6.022 × 10^(23) atoms) / 1 mol) = 1.14 * 10^(24) atoms of P

Atoms of O = 7.6 moles of O * ( (6.022 × 10^(23) atoms) / 1 mol) = 4.58 * 10^(24) atoms of O

Hope this helps! Have a good day!

Answer 2

moles H in 1.90 moles H3PO4

1.90 moles H3PO4 x 3 moles H / 1 mole H3PO4 = 5.70 moles H

moles O in 1.90 moles H3PO4

1.90 moles H3PO4 x 4 moles O / 1 mole H3PO4 = 7.60 moles O

atoms of P in 1.90 moles H3PO4

1.90 moles H3PO4 x 1 mole P / 1 mole H3PO4 x 6.02x1023 atoms of P / mol = 1.14x10²⁴ P atoms

atoms of O in 1.90 moles H3PO4

1.90 moles H3PO4 x 4 moles O / 1 mole H3PO4 x 6.02x1023 O atoms / mole = 4.58x10²⁴ O atoms