Assume the equivalent weight of an acid is 54.0. Calculate the number of mL of 0.326 M NaOH that would be needed to titrate 0.305 g of the acid.

Answer 1

0.305 g acid x 1 equiv / 54 g = 0.005648 equivalents

0.005648 equiv x 1 L / 0.326 equiv = 0.0173 L = 17.3 mls of NaOH needed

or

(0.326 mol / L) (x L) = 0.005648

x = 0.0173 L = 17.3 mls NaOH needed