How many moles of potassium are required to produce 11.0 moles of H2?

Question

How many moles of KOH are produced if 2804.9 moles of H2O are consumed?

2K(s)+2H2O(l)⟶2KOH(aq)+H2(g)

Answer 1

2K(s) +2 H2O(l) ⟶ 2KOH(aq) + H2(g) ... balanced equation

11.0 moles H2 x 2 moles K / mol H2 = 22.0 moles K required

2804.9 moles H2O x 2 moles KOH / 2 moles H2O = 2804.9 moles KOH