
Jon S. answered 04/17/22
Patient and Knowledgeable Math and English Tutor
Find z -scores for bottom 1.5 percent or 1.5th percentile (0.015 probability). that z-score is -2.17
Since normal distribution is symmetric, z-score for top 1.5 percent or 98.5th percentile (0.985 probability) is 2.17
use standardized score z = (x - mean)/SD with mean given as 6 and SD given as 0.8 to find x for z = -2.17 and for 2.17. those will be the values for the 1.5th and 98.5th percentiles:
-2.17 = (x - 6)/0.8
x = -2.17 * 0.8 + 6 = 4.264 ~ 4.3 min = 4.3
2.17 = (x - 6)/0.8
x = 2.17 * 0.8 + 6 = 7.736 ~ 7.7 max = 7.7