At what temperature does 0.011260 moles of Ne in a 893.7 mL container exert a pressure of 0.799 atm?

Answer 1

PV = nRT ... Ideal Gas Law

P = pressure = 0.799 atm

V = volume in L = 893.7 ml x 1 L / 1000 ml =0.8937 L

n = moles = 0.011260 mols

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = ?

Solving for T, we have ...

T = PV / nR = (0.799)(0.8937) / (0.011260)(0.0821)

T = 772K (3 sig, figs,)