J.R. S. answered 04/16/22
Ph.D. University Professor with 10+ years Tutoring Experience
2NaOH(aq) + H2SO4(aq) --> 2H2O(l) + Na2SO4(aq) ... balanced equation
moles NaOH used = 0.0450 L NaOH x 0.150 mol / L = 0.00675 moles NaOH
moles H2SO4 present = 0.00675 mols NaOH x 1 mol H2SO4 / 2 mols NaOH = 0.003375 mols H2SO4
Concentration of H2SO4 = 0.003375 mols H2SO4 / 0.0350 L = 0.0964 M