J.R. S. answered 04/15/22
Ph.D. University Professor with 10+ years Tutoring Experience
25.25 ml H2A x 1.98 g / ml = 49.995 g H2A x 98.0% = 48.995 g H2A
a). 1.0 N H2A = 0.5 M H2A = 0.5 moles H2A / L. Thus, n = moles H2A = 0.5 moles
b). Molarity of diluted solution = moles H2A / L = 0.5 mols / L = 0.5 M
c). Molarity of original solution = (25.25 ml)(x M) = (1000 ml)(0.5 M) and x = 19.8 M
d). Molar mass H2A = g / mol = 48.995 g / 0.5 mols = 98 g / mole
e). Possible identity of H2A = sulfuric acid, H2SO4